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Question

1tan3AtanA1cot3AcotA=


A

tan2A

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B

cot2A

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C

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D

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Solution

The correct options are
B

cot2A


D


1tan3AtanA1cot3AcotA

Substituting cot3A = 1tan3A & cotA = 1tanA

= 1tan3AtanA11tan3A1tanA

= 1tan3AtanAtanA.tan3AtanAtan3A

= 1tan3AtanA+tanA.tan3Atan3AtanA

= (1+tanA.tan3A)tan3AtanA

= 1tan(3AA)

= cot2A

= cot2A12cotA

Options B & D are correct.


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