1-x-3-1-x-5-1 - 3y-227-y-210

The correct option is B x lt; y 1/(x 3)+1/(x+5)=1/3 x^2 4x 21=0 x=7, 3 (y+2)(27 y)=210 y^2 25x+156=0 ⇒ y=12,13 x lt;y ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Solving Inequalities

1/x-3+1/x+5=1...

Question

$\frac{1}{(x - 3)} + \frac{1}{(x + 5)} = 1 / 3$

(y+2)(27-y)=210

x > y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x < y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x $\geq$ y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x $\leq$ y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x=y or relation cannot be established

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Solve the following systems of equations:

$\frac{5}{x + 1} - \frac{2}{y - 1} = \frac{1}{2}$

$\frac{10}{x + 1} + \frac{2}{y - 1} = \frac{5}{2}$ , where $x \neq - 1 a n d y \neq 1$

\frac{1}{2 x} + \frac{1}{3 y} = 2; \frac{1}{3 x} + \frac{1}{2 y} = \frac{13}{6}

\frac{2}{\sqrt{x}} + \frac{3}{\sqrt{y}} = 2; \frac{4}{\sqrt{x}} - \frac{9}{\sqrt{y}} = - 1

\frac{4}{x} + 3 y = 14; \frac{3}{x} - 4 y = 23

\frac{5}{x - 1} + \frac{1}{y - 2} = 2; \frac{6}{x - 1} - \frac{3}{y - 2} = 1

\frac{7 x - 2 y}{x y} = 5; \frac{8 x + 7 y}{x y} = 15

6 x + 3 y = 6 x y; 2 x + 4 y = 5 x y

\frac{10}{x + y} + \frac{2}{x - y} = 4; \frac{15}{x + y} - \frac{5}{x - y} = - 2

\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4}; \frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = \frac{- 1}{8}

Draw the graphs of the following straight −lines:

(i) y = 3 − x; (ii) y = x − 3; (iii) y = 3x − 2; (iv) y = 5 − 3x;

(v) 4y = − x + 3; (vi) 3y = 4x + 1; (vii) x = 4; (viii) 3y = 1.

\frac{x^{- 3} - y^{- 3}}{x^{- 3} y^{- 1} + (x y)^{- 2} + y^{- 3} x^{- 1}}

x + y + z = x y z

\frac{3 x - x^{3}}{1 - 3 x^{2}} + \frac{3 y - y^{3}}{1 - 3 y^{2}} + \frac{3 z - z^{3}}{1 - 3 z^{2}} = \frac{3 x - x^{3}}{1 - 3 x^{2}} \cdot \frac{3 y - y^{3}}{1 - 3 y^{2}} \cdot \frac{3 z - z^{3}}{1 - 3 z^{2}}

Join BYJU'S Learning Program