10x2 - 15x - 63-5x2 - 25x - 12 - 2x - 3-x - 5

[ 10 x^ 2 +15x+63 / 5 x^ 2 25x+12 = 2x+3 /( x 5 ) #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Common Factors

10x2 + 15x + ...

Question

$\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}$

Open in App

Solution

Suggest Corrections

Similar questions

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{{(2 x + 1)}^{2} + {(2 x - 1)}^{2}}{{(2 x + 1)}^{2} - {(2 x - 1)}^{2}} = \frac{17}{8}

\frac{\sqrt{4 x + 1} + \sqrt{x + 3}}{\sqrt{4 x + 1} - \sqrt{x + 3}} = \frac{4}{1}

\frac{{(4 x + 1)}^{2} + {(2 x + 3)}^{2}}{4 x^{2} + 12 x + 9} = \frac{61}{36}

\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 + 12} = \frac{2 x + 3}{x - 5}

(25 x^{5} - 15 x^{4}) \div 5 x^{3}

Join BYJU'S Learning Program