$\frac{101}{7}$ + $\frac{99}{7}$ =

\frac{198}{7}

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\frac{199}{7}

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\frac{200}{7}

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\frac{201}{7}

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Solution

The correct option is C $\frac{200}{7}$
$\frac{101}{7}$ and $\frac{99}{7}$ are like fractions. Hence we can directly add the numerators.
$\frac{101}{7}$ + $\frac{99}{7}$ = $\frac{101 + 99}{7}$
= $\frac{200}{7}$

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Similar questions

7^{99} + 7^{100} + 7^{101}

If you add $\frac{101}{7}$ to $\frac{99}{7}$ , you will get -

Solve :

99x+101y=499

101x+99y= 501

(With steps)

$- 7 \times - 13 = 101$

Solve the following systems of equations:
99x + 101y = 499
101x + 99y = 501

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