The correct option is A The given fractions are nbsp;11/25 and 16/25. They are like fractions because their denominator is the same. nbsp; To compare like f ...

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Standard IV

Mathematics

Comparison of Fractions

11/2516/25

Question

$\frac{11}{25}$ $\frac{16}{25}$

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Solution

The correct option is A $<$
The given fractions are $\frac{11}{25}$ and $\frac{16}{25}$ .

They are like fractions because their denominator is the same.

To compare like fractions we need to compare their numerators.

11 < 16

Therefore, $\frac{11}{25} < \frac{16}{25}$ .

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Similar questions

\frac{11}{25}

\frac{16}{25}

Find the degree of the polynomial

${(x + (x^{3} - 1)^{\frac{1}{2}})}^{5} + {(x - (x^{3} - 1)^{\frac{1}{2}})}^{5}$

Q. Evaluate:

(\frac{\sqrt{625}}{11} * \frac{14}{\sqrt{25}} * \frac{11}{\sqrt{196}})

Q. The expansion

{{x + (x^{3} - 1)}^{1 / 2}}^{5} + {{x - (x^{3} - 1)}^{1 / 2}}^{5}

is a polynomial of degree

\frac{- 7}{5} + (\frac{2}{- 11} + \frac{- 13}{25}) = (\frac{- 7}{5} + \frac{2}{- 11}) + \frac{- 13}{25}

This property is

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1125 1625

The correct option is A <The given fractions are 1125 and 1625. They are like fractions because their denominator is the same. To compare like fractions we need to compare their numerators. 11 < 16 Therefore, 1125<1625.

$\frac{11}{25}$ $\frac{16}{25}$

The correct option is A $<$
The given fractions are $\frac{11}{25}$ and $\frac{16}{25}$ .

They are like fractions because their denominator is the same.

To compare like fractions we need to compare their numerators.

11 < 16

Therefore, $\frac{11}{25} < \frac{16}{25}$ .