$\frac{12}{18} + \frac{5}{15}$ =

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1733

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\frac{7}{18}

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Solution

The correct option is A 1
Note that
$\frac{12}{18}$ and $\frac{5}{15}$ can be simplified further as follows using the facts that HCF of 12 and 18 is 6, and that of 5 and 15 is 5:
$\frac{12 \div 6}{18 \div 6} = \frac{2}{3}$ and $\frac{5 \div 5}{15 \div 5} = \frac{1}{3}$ .
Now, we have $\frac{12}{18} + \frac{5}{15} = \frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 1$ .

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Similar questions

\frac{- 12}{5} + \frac{31}{10} + \frac{11}{- 15} + \frac{- 7}{- 18}

Solve:

(a) (b)

(e) (f)

(g) (h)

(i)

Class:	$3 - 6$	$6 - 9$	$9 - 12$	$12 - 15$	$15 - 18$	$18 - 21$	$21 - 24$
Frequency:	$2$	$5$	$10$	$23$	$21$	$12$	$3$

\frac{15^{3} \times 18^{2}}{3^{5} \times 5^{4} \times 12^{2}}

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