Question

Question 121

$\frac{16\times {10}^2\times 64}{2^4\times 4^2}$

Answer 1

Using laws of exponents $a^m÷a^n=(a{)}^{m-n}and{a}^m\times a^n=a^{m+n}\therefore \frac{16\times {10}^2\times 64}{2^4\times 4^2}=\frac{2^4\times {10}^2\times 2^6}{2^4\times (2^2{)}^2}=\frac{2^4\times {10}^2\times 2^6}{2^4\times 2^4}=\frac{2^{4+6}\times {10}^2}{2^{4+4}}=\frac{2^{10}\times {10}^2}{2^8}=2^{10-8}\times {10}^2=2^2\times {10}^2=4\times 100=400$