$\frac{2}{11}$ + $\frac{7}{11}$ =

\frac{6}{11}

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\frac{5}{11}

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\frac{9}{11}

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Solution

The correct option is D $\frac{9}{11}$
While adding two like fractions, we can directly add the numerators, while retaining the denominator as it is. Hence, $\frac{2}{11} + \frac{7}{11} = \frac{2 + 7}{11} = \frac{9}{11}$

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Similar questions

\frac{2}{11}

\frac{7}{11}

\frac{\sqrt{11} - \sqrt{7}}{\sqrt{11} + \sqrt{7}} \times \frac{\sqrt{11} - \sqrt{7}}{\sqrt{11} - \sqrt{7}}

Evaluate

$\frac{- 2}{7} + \frac{- 4}{11} + \frac{- 12}{7} + \frac{- 7}{11}$

The value of

$\frac{- 2}{7} + \frac{- 4}{11} + \frac{- 12}{7} + \frac{- 7}{11}$ is ___.

Match the column

$\begin{matrix} Column A & Column B 1.cos \frac{2 π}{7} + cos \frac{4 π}{7} + cos \frac{6 π}{7} & A.0 2.cos \frac{π}{7} + cos \frac{2 π}{7} +cos \frac{3 π}{7} + cos \frac{4 π}{7} + cos \frac{5 π}{7} + cos \frac{6 π}{7} & B. \frac{1}{2} 3.sin \frac{π}{11} + sin \frac{3 π}{11} + sin \frac{5 π}{11} + sin \frac{7 π}{11} + sin \frac{9 π}{11} & C. \frac{- 1}{2} \end{matrix}$

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211+711=

The correct option is D 911While adding two like fractions, we can directly add the numerators, while retaining the denominator as it is. Hence, 211+711=2+711=911

$\frac{2}{11}$ + $\frac{7}{11}$ =

The correct option is D $\frac{9}{11}$
While adding two like fractions, we can directly add the numerators, while retaining the denominator as it is. Hence, $\frac{2}{11} + \frac{7}{11} = \frac{2 + 7}{11} = \frac{9}{11}$