Now, 215−110 =2×215×2−1×310×3 =430−330=4−330=130.
=130
Subtract: 215−110= _____
The maximum kinetic energy of the photoelectrons is found to be 6.63 × 10−19 J. When the metal is irradiated with a radiation of frequency 2 × 1015 Hz, the threshold frequency of the metal is about
Multiply:
(1) (−10) by (−15)
(2) (+35) by (−5)
(3) (−15) by (+8)
(4) (+10) by (−10)
(5) (+100) by (−10)