$\frac{2}{3}$ of a class took Mathematics and the rest Computer Science. If there are $48$ students in a class, how many students took Computer Science $?$

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Solution

Total students in the class $= 48$
Total number of students who took Mathematics
$= \frac{2}{3} \times 48 = 32$
Students who took Computer Science $=$ total students in the class $-$ students who took Mathematics
$= 48 - 32 = 16$
Hence, there are $16$ students, who took Computer Science.

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23 of a class took Mathematics and the rest Computer Science. If there are 48students in a class, how many students took Computer Science ?

Total students in the class =48Total number of students who took Mathematics =23×48=32Students who took Computer Science = total students in the class - students who took Mathematics =48-32=16Hence, there are 16 students, who took Computer Science.

$\frac{2}{3}$ of a class took Mathematics and the rest Computer Science. If there are $48$ students in a class, how many students took Computer Science $?$

Total students in the class $= 48$
Total number of students who took Mathematics
$= \frac{2}{3} \times 48 = 32$
Students who took Computer Science $=$ total students in the class $-$ students who took Mathematics
$= 48 - 32 = 16$
Hence, there are $16$ students, who took Computer Science.