The correct option is C 2^ 10Given:2^5/2^8× 2^ 7 2^5/2^8× 2^ 7=2^5× 2^ 7/2^8= nbsp;2^5+( 7)/2^8 (∵ a^m× a^n=a^m+n) nbsp; nbsp;2^5+( 7)/2^8=2^5 7/2^8 =2^ 2 ...

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Byju's Answer

Standard XI

Mathematics

Properties of Cube Root of a Complex Number

25/28× 2-7=

Question

$\frac{2^{5}}{2^{8}} \times 2^{- 7}$ =

2^{10}

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2^{6}

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2^{- 10}

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2^{- 4}

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Solution

The correct option is C $2^{- 10}$
Given: $\frac{2^{5}}{2^{8}} \times 2^{- 7}$

$\frac{2^{5}}{2^{8}} \times 2^{- 7} = \frac{2^{5} \times 2^{- 7}}{2^{8}} = \frac{2^{5 + (- 7)}}{2^{8}}$
$(∵ a^{m} \times a^{n} = a^{m + n})$
$\frac{2^{5 + (- 7)}}{2^{8}} = \frac{2^{5 - 7}}{2^{8}}$
$= \frac{2^{- 2}}{2^{8}} = 2^{- 2 - 8} = 2^{- 10}$
$(∵ \frac{a^{m}}{a^{n}} = a^{m - n})$

Hence, $\frac{2^{5}}{2^{8}} \times 2^{- 7} = 2^{- 10}$

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Similar questions

Solve:-

$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$

Question 98(iv)

Simplify
$(2^{5} \div 2^{8}) \times 2^{- 7}$

Question 98(iv)

Simplify
$(2^{5} \div 2^{8}) \times 2^{- 7}$

Q. The value of

(\frac{2^{5}}{2^{8}}) \times 2^{- 7}

Q. The value of

\frac{(2^{5})}{(2^{8})} \times (2^{- 7})

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2528×2−7 =

The correct option is C 2−10Given:2528× 2−7 2528× 2−7=25× 2−728=25+(−7)28 (∵am×an=am+n) 25+(−7)28=25−728 =2−228=2−2−8=2−10 (∵aman=am−n) Hence, 2528× 2−7=2−10

$\frac{2^{5}}{2^{8}} \times 2^{- 7}$ =