2-5-2-8- 2-7 - nbsp-2-102-62-102-4

The correct option is C 2^ 10Given:2^5/2^8× 2^ 7 2^5/2^8× 2^ 7=2^5× 2^ 7/2^8= nbsp;2^5+( 7)/2^8 (∵ a^m× a^n=a^m+n) nbsp; nbsp;2^5+( 7)/2^8=2^5 7/2^8 =2^ 2 ...

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Byju's Answer

Standard VII

Mathematics

Division of Powers with the Same Base

2^5/2^8× 2^-7...

Question

$\frac{2^{5}}{2^{8}} \times 2^{- 7}$ =

2^{10}

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2^{6}

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2^{- 10}

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2^{- 4}

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Solution

The correct option is C $2^{- 10}$
Given: $\frac{2^{5}}{2^{8}} \times 2^{- 7}$

$\frac{2^{5}}{2^{8}} \times 2^{- 7} = \frac{2^{5} \times 2^{- 7}}{2^{8}} = \frac{2^{5 + (- 7)}}{2^{8}}$
$(∵ a^{m} \times a^{n} = a^{m + n})$
$\frac{2^{5 + (- 7)}}{2^{8}} = \frac{2^{5 - 7}}{2^{8}}$
$= \frac{2^{- 2}}{2^{8}} = 2^{- 2 - 8} = 2^{- 10}$
$(∵ \frac{a^{m}}{a^{n}} = a^{m - n})$

Hence, $\frac{2^{5}}{2^{8}} \times 2^{- 7} = 2^{- 10}$

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Similar questions

Find the number from each of the following expanded forms:

(a) 8 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰

(b) 4 × 10⁵+ 5 × 10³+ 3 × 10²+ 2 × 10⁰

(d) 9 × 10⁵ + 2 × 10² + 3 × 10¹

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

\frac{2^{5}}{2^{8}} \times 2^{- 7}

= _____.

Solve:-

$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$

Question 98(iv)

Simplify
$(2^{5} \div 2^{8}) \times 2^{- 7}$

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2528×2−7 =

The correct option is C 2−10Given:2528× 2−7 2528× 2−7=25× 2−728=25+(−7)28 (∵am×an=am+n) 25+(−7)28=25−728 =2−228=2−2−8=2−10 (∵aman=am−n) Hence, 2528× 2−7=2−10

$\frac{2^{5}}{2^{8}} \times 2^{- 7}$ =