The correct option is B 2^ 10Given: nbsp;2^5/2^8× 2^ 7 We know, a^m/a^n=a^m n. So, 2^5/2^8× 2^ 7 =2^5 8×2^ 7 = nbsp;2^ 3×2^ 7 =2^ 3 nbsp; 7 (∵ ...

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Exponents with like Bases

25/28× 2-7 = ...

Question

$\frac{2^{5}}{2^{8}} \times 2^{- 7}$ = _____.

2^{5}

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2^{- 5}

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2^{10}

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2^{- 10}

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Solution

The correct option is D $2^{- 10}$
Given: $\frac{2^{5}}{2^{8}} \times 2^{- 7}$

We know, $\frac{a^{m}}{a^{n}} = a^{m - n}$ .

$So, \frac{2^{5}}{2^{8}} \times 2^{- 7} = 2^{5 - 8} \times 2^{- 7} = 2^{- 3} \times 2^{- 7} = 2^{- 3 - 7} (∵ a^{m} \times a^{n} = a^{m + n}) = 2^{- 10}$

Hence, $\frac{2^{5}}{2^{8}} \times 2^{- 7} = 2^{- 10}$

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$(\frac{2^{5}}{2^{8}}) \times 2^{- 7}$

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$(2^{5} \div 2^{8}) \times 2^{- 7}$

Question 98(iv)

Simplify
$(2^{5} \div 2^{8}) \times 2^{- 7}$

\frac{(2^{5})}{(2^{8})} \times (2^{- 7})

(\frac{2^{5}}{2^{8}}) \times 2^{- 7}

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