2-5 m n n m -5-2 m m n n -A- m m - nB- m nm-nC- mn mnD- n m - n

The correct option is B (mn)^m+n 2/5m^nn^m ×5/2m^mn^n = 2/5×5/2× m^n × m^m × n^m × n^n = 1 × m^n+m× n^m+n = (mn)^m+n ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of Monomials

2/5 m n n m ×...

Question

$\frac{2}{5} m^{n} n^{m} \times \frac{5}{2} m^{m} n^{n}$ =

$(n)^{m + n}$

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$(m)^{m + n}$

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$(m n)^{m + n}$

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$(m n)^{m n}$

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Solution

The correct option is C
$(m n)^{m + n}$

$\frac{2}{5} m^{n} n^{m} \times \frac{5}{2} m^{m} n^{n}$

= $\frac{2}{5} \times \frac{5}{2} \times m^{n} \times m^{m} \times n^{m} \times n^{n}$

= $1 \times m^{n + m} \times n^{m + n}$

= $(m n)^{m + n}$

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25mnnm×52mmnn =

The correct option is C (mn)m+n 25mnnm×52mmnn = 25×52×mn×mm×nm×nn = 1×mn+m×nm+n = (mn)m+n

$\frac{2}{5} m^{n} n^{m} \times \frac{5}{2} m^{m} n^{n}$ =

The correct option is C
$(m n)^{m + n}$

$\frac{2}{5} m^{n} n^{m} \times \frac{5}{2} m^{m} n^{n}$

= $\frac{2}{5} \times \frac{5}{2} \times m^{n} \times m^{m} \times n^{m} \times n^{n}$

= $1 \times m^{n + m} \times n^{m + n}$

= $(m n)^{m + n}$