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Question

212×313×4141015×535÷343×575435×6

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Solution


212×313×(2)2×14(2×5)15×535×435×6343×575
=212×313×212215×515×535×(2)2(35)×(2×3)343×(5)15=[2(12+12(15))×313×5(15+35)]×[2(65+1)×31.43×5(15)]=(265×313×5(25))×(215×313×575)
=2(6515)×3(1313)×5(25+75)=255×3×555=21×1×51=10

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