The correct option is C 2 √(21)/7 2√(3)/√(7) = 2 √(3)/√(7)×√(7)/√(7) =2 √(21)/7 ...

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Byju's Answer

Standard IX

Mathematics

Operations on Monomial Surds

2 √3/√7=-

Question

$\frac{2 \sqrt{3}}{\sqrt{7}} =$ ___

$\frac{2 \sqrt{21}}{7}$

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$2 \sqrt{21}$

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$\frac{2 \sqrt{7}}{\sqrt{3}}$

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$1$

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Solution

The correct option is A
$\frac{2 \sqrt{21}}{7}$

$\frac{2 \sqrt{3}}{\sqrt{7}} = \frac{2 \sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}}$

$= \frac{2 \sqrt{21}}{7}$

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Similar questions

Q. Using appropriates, find:

\frac{2}{3} \times \frac{- 5}{7} + \frac{7}{3} + \frac{2}{3} \times \frac{- 2}{7}

Q. If 5 + 3 = 15, 5 – 3 = 8 and 5 ÷ 3 = 2, then 7 + 7 – 7 ÷ 7 = ?.

यदि 5 + 3 = 15, 5 – 3 = 8 तथा 5 ÷ 3 = 2, तब 7 + 7 – 7 ÷ 7 = ?

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Question 6

Q. Simplify :

\frac{3^{5} 2^{2} 7^{3}}{7^{2} 3^{3} 2^{4}}

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2√3√7= ___

The correct option is A 2√217 2√3√7=2√3√7×√7√7 =2√217

$\frac{2 \sqrt{3}}{\sqrt{7}} =$ ___

The correct option is A
$\frac{2 \sqrt{21}}{7}$

$\frac{2 \sqrt{3}}{\sqrt{7}} = \frac{2 \sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}}$

$= \frac{2 \sqrt{21}}{7}$