2 -3-7- -1-2 -21-7-2 -21-2 -7-3-

The correct option is B 2 √(21)/7 2√(3)/√(7) = 2 √(3)/√(7)×√(7)/√(7) =2 √(21)/7 ...

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Byju's Answer

Standard IX

Mathematics

Rationalisation of Denominator

2 √(3)/√(7)= ...

Question

$\frac{2 \sqrt{3}}{\sqrt{7}} =$ ___

$\frac{2 \sqrt{21}}{7}$

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$2 \sqrt{21}$

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$\frac{2 \sqrt{7}}{\sqrt{3}}$

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$1$

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Solution

The correct option is A
$\frac{2 \sqrt{21}}{7}$

$\frac{2 \sqrt{3}}{\sqrt{7}} = \frac{2 \sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}}$

$= \frac{2 \sqrt{21}}{7}$

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Similar questions

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Which of the following is an orthogonal matrix-

A. $[\begin{matrix} 1 & 0 1 & 0 \end{matrix}]$ B. $[\begin{matrix} 1 & 0 0 & 1 \end{matrix}]$ C. $[\begin{matrix} 1 & 1 1 & 0 \end{matrix}]$ D. $[\begin{matrix} 0 & 0 1 & 1 \end{matrix}]$

\sqrt[2010]{2 \sqrt{7} - 3 \sqrt{3}} \times \sqrt[4020]{55 + 12 \sqrt{21}} = ?

Q. Simplify:

5 \frac{1}{3}

\times 2 \frac{1}{2}

\times 1 \frac{2}{3}

\times 6 \frac{5}{7}

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2√3√7= ___

The correct option is A 2√217 2√3√7=2√3√7×√7√7 =2√217

$\frac{2 \sqrt{3}}{\sqrt{7}} =$ ___

The correct option is A
$\frac{2 \sqrt{21}}{7}$

$\frac{2 \sqrt{3}}{\sqrt{7}} = \frac{2 \sqrt{3}}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}}$

$= \frac{2 \sqrt{21}}{7}$