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Question

2x+1(x1)(x2+1)=Ax1+Bx+cx2+1ABC=

A
8
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B
6
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C
4
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D
2
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Solution

The correct option is B 6
2x+1(x1)(x2+1)=A(x2+1)+(Bx+C)(x1)(x1)(x2+1)
So, equating the order's of the power of x we get
A+B=O(1)forx2 co-efficient.
AC=1(2)for1 co-efficient
B+C=2(3)forx co-efficient
AB=3 from (2) and (3)
So,
A=(1.5);B=(1.5)
and c=0.5
So, ABC=6
ABC=6

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