Question

$(\frac{3}{2}m+\frac{2}{3}n)(\frac{3}{2}m-\frac{2}{3}n)$

Answer 1

$(\frac{3m}{2}+\frac{2n}{3})(\frac{3m}{2}-\frac{2n}{3})$ which is of the form $(a+b)(a-b)=a^2-b^2$

$={\left(\frac{3m}{2}\right)}^2-{\left(\frac{2n}{3}\right)}^2$

$=\frac{9m^2}{4}-\frac{4n^2}{9}$