The correct option is B -10
Given:
3(2x + 5)x + 1=6xx − 2
On cross-multiplication of denominators,
⇒3(2x+5)×(x−2)=(6x)×(x+1)
⇒(6x+15)×(x−2)=(6x)×(x+1)
⇒6x2−12x+15x−30=6x2+6x
Subtracting 6x2 on both sides, we get,
⇒−12x+15x−30=6x
Separate like terms, we get,
⇒−12x+15x−6x=30
⇒−3x=30
⇒x=30−3
⇒x=−10