$\frac{33}{121}$ reduced to its simplest form is ______

$\frac{1}{11}$

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$\frac{3}{11}$

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$\frac{9}{11}$

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$\frac{11}{3}$

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Solution

The correct option is B
$\frac{3}{11}$

$\frac{33}{121} = \frac{/ 11 \times 3}{/ 11 \times 11} = \frac{3}{11}$

Suggest Corrections

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