-360-Order-of-rotationCentre of rotationPoint of rotationAngle of rotationLine of symmetry

The correct option is C Angle of rotationAngle of rotation = 360^∘/Order of rotation ...

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Centre of Rotational Symmetry

_____=360^∘/O...

Question

_____= $\frac{360^{\circ}}{O r d e r o f r o t a t i o n}$

Centre of rotation

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Angle of rotation

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Point of rotation

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Line of symmetry

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Solution

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Similar questions

Draw, wherever possible, a rough sketch of

(i) a triangle with both line and rotational symmetries of order more than 1.

(ii) a triangle with only line symmetry and no rotational symmetry of order more than 1.

(iii) a quadrilateral with a rotational symmetry of order more than 1 but not a line symmetry.

(iv) a quadrilateral with line symmetry but not a rotational symmetry of order more than 1.

Order of symmetry, angle of rotation of isosceles triangle

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