3a−5z3b−5y=3a+5z3b+5y. Then, ab=zy
True
False
3a−5z3b−5y=3a+5z3b+5y
⇒ 3a−5z3a+5z=3b−5y3b+5y [Applying alternendo]
⇒3a−5z+3a+5z3a−5z−3a−5z=3b−5y+3b+5y3b−5y−3b−5y [Applying componendo and dividendo]
⇒6a−10z=6b−10y
⇒az=by
∴ab=zy [Applying alternendo]