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Question

4cot230+1sin2302cos245sin20

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Solution

= 4 over open parentheses square root of 3 close parentheses squared plus fraction numerator 1 over denominator begin display style left parenthesis 1 half right parenthesis squared end style end fraction minus 2 open parentheses fraction numerator 1 over denominator square root of 2 end fraction close parentheses squared minus 0 4 over 3 plus 4 over 1 minus 1 minus 0 fraction numerator 4 plus 12 minus 3 over denominator 3 end fraction 13 over 3


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