$\frac{41}{3}$ is =

13 + \frac{2}{3}

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13 + \frac{3}{2}

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3 + \frac{2}{3}

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Solution

The correct option is A $13 + \frac{2}{3}$
$\frac{41}{3}$ is an improper fraction. It can be written as a mixed fraction which is $13 \frac{2}{3}$ . ( $13 + \frac{2}{3}$ ).
Here 13 is the whole number while $\frac{2}{3}$ is the proper fraction part of the mixed fraction .

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Similar questions

4 \frac{1}{2} \times 4 \frac{1}{3} - 8 \frac{1}{3} \div 5 \frac{2}{3} = ? .

4 \frac{1}{2} z + 4 \frac{1}{3}

z = 100

z

4 \frac{1}{3} + 5 \frac{2}{3}

4 \frac{1}{3} \div \frac{2}{3}

- 59, - 41, 73, - 92, 81, - (- 41)

- 3

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