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Byju's Answer
Standard VI
Mathematics
Division of a Monomial by a Monomial
49 x2 y z2/7 ...
Question
49
x
2
y
z
2
7
y
2
z
3
=
?
A
7
x
y
z
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B
7
x
2
y
z
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C
7
x
3
y
z
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D
7
x
2
y
2
z
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Solution
The correct option is
B
7
x
2
y
z
49
x
2
y
z
2
7
y
2
z
3
=
(
7
y
z
2
)
(
7
x
2
)
(
7
y
z
2
)
(
y
z
)
=
7
x
2
y
z
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0
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Q.
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, the coefficient of
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