$\frac{5}{2}$ is __ $\frac{3}{2}$ .

greater than

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smaller than

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equal to

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half of

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Solution

The correct option is A greater than
Here both are like fractions with the denominator as 2.

We compare the numerators and we get 5 > 3.

$∴ \frac{5}{2}$ is greater than $\frac{3}{2}$ .

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Similar questions

$\int \frac{1}{2 + 3 s i n x} d x$

${(\frac{2}{3})}^{3} \times {(\frac{5}{7})}^{3}$ is equal to

$(a) {(\frac{2}{3} \times \frac{5}{7})}^{9}$
$(b) {(\frac{2}{3} \times \frac{5}{7})}^{6}$
$(c) {(\frac{2}{3} \times \frac{5}{7})}^{3}$
$(d) {(\frac{2}{3} \times \frac{5}{7})}^{0}$

Q. Evaluate

\frac{\sqrt{5}}{\sqrt{3} + \sqrt{2}} - \frac{3 \sqrt{3}}{\sqrt{5} + \sqrt{2}} + \frac{2 \sqrt{2}}{\sqrt{5} + \sqrt{3}}

Simplify:

(i) $\frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}} + \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}$

(ii) $\frac{1}{2 + \sqrt{3}} + \frac{2}{\sqrt{5} - \sqrt{3}} + \frac{1}{2 - \sqrt{5}}$

(iii) $\frac{2}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{2}} - \frac{3}{\sqrt{5} + \sqrt{2}}$

The HCF of $2^{2} \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11, 2 \times 3^{2} \times 5^{2}, 2^{4} \times 3^{4} \times 5^{3} \times 11$ is:

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52 is __ 32.

The correct option is A greater thanHere both are like fractions with the denominator as 2. We compare the numerators and we get 5 > 3. ∴52 is greater than 32.

$\frac{5}{2}$ is __ $\frac{3}{2}$ .

The correct option is A greater than
Here both are like fractions with the denominator as 2.

We compare the numerators and we get 5 > 3.

$∴ \frac{5}{2}$ is greater than $\frac{3}{2}$ .