Step 1 : Converting into equivalent fraction, Given : 6/21=□/7⇒ 6÷3/21÷3=□/7 ⇒ 2/7=□/7Step 2: Comparing both sides On comparing ...

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Standard VIII

Mathematics

Square Roots

6/21=□/7

Question

$\frac{6}{21} = \frac{□}{7}$

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Solution

Step 1 :- Converting into equivalent fraction,
Given :- $\frac{6}{21} = \frac{□}{7}$
⇒ $\frac{6 \div 3}{21 \div 3} = \frac{□}{7}$ ⇒ $\frac{2}{7} = \frac{□}{7}$
Step 2:- Comparing both sides
On comparing both sides,
We will get, $□ = 2$
Therefore, the value of $□$ is $2$

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Similar questions

Find the missing numeral $:$

$\frac{5}{7} =$ $\frac{□}{56}$

Find

(i) (ii) (iii)

(iv) (v)

Question 21
The reciprocal of $\frac{- 3}{8} \times (\frac{- 7}{13})$ is
(a) $\frac{104}{21}$
(b) $\frac{- 104}{21}$
(c) $\frac{21}{104}$
(d) $\frac{- 21}{104}$

Q. Complete the following activities and rewrite it:
(i) If

△ A B C \sim △ P Q R, A (△

A B C) = 81 {c m}^{2}, A (△ P Q R) =

121 {c m}^{2}, B C = 6.3 c m

, then complete the following activity to find QR.
Activity :

△ A B C \sim △ P Q R \dots \dots

(given)

\begin{matrix} ∴ \frac{A (△ A B C)}{A (△ P Q R)} = \frac{□}{{Q R}^{2}} \dots \dots \dots \dots ∴ \frac{□}{121} = \frac{(6.3)^{2}}{{Q R}^{2}} ∴ \frac{□}{11} = \frac{6.3}{Q R} \dots \dots . (Taking square root of both sides) Q R = \frac{6.3 \times 11}{□} Q R = □ c m \end{matrix}

The sum of the series $\frac{2}{3!} + \frac{4}{5!} + \frac{6}{7!} + . . .$ to $\infty$ = $\frac{a}{e}$ . Find $(a + 3)^{2}$ .

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621=□7

Step 1 :- Converting into equivalent fraction, Given :- 621=□7⇒ 6÷321÷3=□7 ⇒ 27=□7Step 2:- Comparing both sides On comparing both sides, We will get, □=2Therefore, the value of □ is 2

$\frac{6}{21} = \frac{□}{7}$

Step 1 :- Converting into equivalent fraction,
Given :- $\frac{6}{21} = \frac{□}{7}$
⇒ $\frac{6 \div 3}{21 \div 3} = \frac{□}{7}$ ⇒ $\frac{2}{7} = \frac{□}{7}$
Step 2:- Comparing both sides
On comparing both sides,
We will get, $□ = 2$
Therefore, the value of $□$ is $2$