Assume missing numbers be a,band c.6/a=b/8=3/c=24/16Here, b/8=24/16b=8× 24/16=12And, 6/a=24/16a=16× 6/24=4Also, 3/c=24/16c=16× 3/24=2Hence, 6/4=12/8=3/2=24/16 ...

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Byju's Answer

Standard V

Mathematics

LCD Method

6/=/8=3/=24/1...

Question

$\frac{6}{} = \frac{}{8} = \frac{3}{} = \frac{24}{16}$

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Solution

Assume missing numbers be $a, b$ and $c$ .
$\frac{6}{a} = \frac{b}{8} = \frac{3}{c} = \frac{24}{16}$
Here, $\frac{b}{8} = \frac{24}{16}$
$b = \frac{8 \times 24}{16} = 12$
And, $\frac{6}{a} = \frac{24}{16}$
$a = \frac{16 \times 6}{24} = 4$
Also, $\frac{3}{c} = \frac{24}{16}$
$c = \frac{16 \times 3}{24} = 2$
Hence, $\frac{6}{4} = \frac{12}{8} = \frac{3}{2} = \frac{24}{16}$

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Similar questions

Write $=$ or $\neq$ in the place holder.
$\frac{1}{8}$ $□$ $\frac{3}{4}$

The sum of the series $\frac{2}{3!} + \frac{4}{5!} + \frac{6}{7!} + . . .$ to $\infty$ = $\frac{a}{e}$ . Find $(a + 3)^{2}$ .

Q. Simplify :

2^{\frac{1}{4}} . 4^{\frac{1}{8}} . 8^{\frac{1}{16}} . 16^{\frac{1}{32}} . . . . . .

$2^{\frac{1}{4}}$ . $4^{\frac{1}{8}}$ . $8^{\frac{1}{16}}$ . $16^{\frac{1}{32}}$ ................ is equal to

Q. Compare

\frac{8}{20}

and

\frac{8}{16}

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6=8=3=2416

Assume missing numbers be a,band c.6a=b8=3c=2416Here, b8=2416b=8×2416=12And, 6a=2416a=16×624=4Also, 3c=2416c=16×324=2Hence, 64=128=32=2416

$\frac{6}{} = \frac{}{8} = \frac{3}{} = \frac{24}{16}$