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Byju's Answer
Standard IX
Mathematics
Algebraic Identities
61/303 - 5/63...
Question
(
61
30
)
3
−
(
5
6
)
3
−
(
6
5
)
3
is equal to
A
16
15
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B
61
10
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C
5
2
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D
61
90
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Solution
The correct option is
B
61
10
(
61
30
)
3
−
(
5
6
)
3
−
(
6
5
)
3
=
[
(
6
5
)
3
+
(
5
6
)
3
]
3
−
(
6
5
)
3
−
(
5
6
)
3
=
(
6
5
)
3
+
(
5
6
)
3
+
3
(
6
5
)
(
5
6
)
(
6
5
+
5
6
)
−
(
6
5
)
3
−
(
5
6
)
3
=
3
(
6
5
+
5
6
)
=
3
×
(
36
+
25
)
30
=
61
10
Hence, the correct answer is option (2).
Suggest Corrections
2
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The sum of the series
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(
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(
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2
−
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+
30
2
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(
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Q.
Given that 1 + 2 + 3 + 4 + 5 + 6 = 21, the sum of 61 + 62 + 63 + 64 + 65 + 66 is
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Q.
5
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+
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-
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×
5
n
+
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×
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-
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×
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is equal to
(a)
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(b)
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(d)
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