Question

$\frac{7}{12}+\frac{8}{9}-\frac{5}{6}$

Answer 1

Step 1:- Make the denominator of both fractions same.

Multiply $\frac{7}{12}$by $3$

$\frac{7}{12}$$=\frac{7\times 3}{12\times 3}=\frac{21}{36}$

Multiply $\frac{8}{9}$ by $4$.

$\frac{8}{9}=\frac{8\times 4}{9\times 4}=\frac{32}{36}$

Multiply $\frac{5}{6}$by $6$.

$\frac{5}{6}=\frac{5\times 6}{6\times 6}=\frac{30}{36}$

Step 2:- Add $\frac{21}{36}$ and $\frac{32}{36}$

$\frac{21}{36}+\frac{32}{36}=\frac{21+32}{36}=\frac{53}{36}$

Step 3:- Subtract $\frac{30}{36}$ from $\frac{53}{36}$

$\frac{53}{36}$$-$$\frac{30}{36}$$=\frac{53-30}{36}=\frac{23}{36}$

Hence, $\frac{23}{36}$ is the required solution.