The correct option is B 1/8Let us consider 7/8 3/4. Note that the LCM of 4 and 8 is 8. Now, 7/8 3/4 =7 × 1/8 × 1 3 × 2/4 × 2 =7/8 6/8=7 6/8=1/8. ...

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Standard VI

Mathematics

Subtraction of Fractions

7/8-3/4=1/41/...

Question

$\frac{7}{8} - \frac{3}{4}$ =

\frac{1}{4}

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\frac{1}{8}

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\frac{5}{8}

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\frac{3}{8}

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Solution

The correct option is B $\frac{1}{8}$
Let us consider $\frac{7}{8} - \frac{3}{4}$ .
Note that the LCM of 4 and 8 is 8.

Now, $\frac{7}{8} - \frac{3}{4}$ = $\frac{7 \times 1}{8 \times 1} - \frac{3 \times 2}{4 \times 2}$

$= \frac{7}{8} - \frac{6}{8} = \frac{7 - 6}{8} = \frac{1}{8}$ .

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Similar questions

Q. Write the additive inverse:

(1)

\frac{5}{9}

(2)

\frac{- 8}{3}

(3)

\frac{- 10}{17}

(4)

\frac{9}{2}

(5) −1
(6) 7
(7) −25
(8) 0

Question 83 (i)

Which is greater in the following?
$\frac{3}{4}, \frac{7}{8}$

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

Use the sign of >, < or = in the box to make the statements true.

Write the multiplicative inverse of the following:

(1) $\frac{13}{4}$
(2) $\frac{4}{13}$
(3) $\frac{- 3}{8}$
(4) $\frac{- 8}{3}$
(5) $\frac{- 16}{7}$
(6) $\frac{7}{6}$
(7) 5
(8) −2
(9) 1
(10) 11

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78−34=

The correct option is B 18Let us consider 78−34. Note that the LCM of 4 and 8 is 8. Now, 78−34 =7×18×1−3×24×2 =78−68=7−68=18.

$\frac{7}{8} - \frac{3}{4}$ =

The correct option is B $\frac{1}{8}$
Let us consider $\frac{7}{8} - \frac{3}{4}$ .
Note that the LCM of 4 and 8 is 8.

Now, $\frac{7}{8} - \frac{3}{4}$ = $\frac{7 \times 1}{8 \times 1} - \frac{3 \times 2}{4 \times 2}$

$= \frac{7}{8} - \frac{6}{8} = \frac{7 - 6}{8} = \frac{1}{8}$ .