$\frac{8}{3}$ $>$ $\frac{9}{4}$

a² + b² – 2ab

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a² + b² + 2ab

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Solution

The correct option is A
a² + b² – 2ab

To compare the given numbers, we will make the denominator same.
So, common denominator will be L.C.M of $4$ and $3$ , which is $12$ .
$\Rightarrow \frac{8}{3} = \frac{32}{12}$

And
$\frac{9}{4} = \frac{27}{12}$
Clearly, $\frac{32}{12} > \frac{27}{12}$
Hence, $\frac{8}{3} > \frac{9}{4}$

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Similar questions

Factorise $9 x^{2} - 64$

Q. (1) 5, 3, 2, 9 (2) 2, 4, 3, 9
(3) 1, 4, 3, 8 (4) 3, 2, 3, 8

Fill in the blanks:

$(i) - 4 \times \frac{7}{9} = \frac{7}{9} \times$ ___

$(i i) \frac{5}{11} \times \frac{- 3}{8} = \frac{- 3}{8} \times$ ___

$(i i i) \frac{1}{2} \times (\frac{3}{4} + \frac{- 5}{12}) = \frac{1}{2} \times$ ____ $+ (\times) \frac{- 5}{12}$

$(i v) \frac{- 4}{5} \times \frac{5}{7} \times$ ___ $= (\frac{- 4}{5} \times \frac{5}{7}) \times \frac{- 8}{9}$

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

Q. Workout the following :

a) \frac{5}{13} + \frac{4}{13} =_____

b) \frac{15}{23} - \frac{11}{23} =_____

c) \frac{3}{4} + \frac{3}{8} =_____

d) \frac{8}{9} - \frac{4}{9} =_____

e) \frac{12}{13} - \frac{5}{13} =_____

f) \frac{3}{4} - \frac{3}{8} =_____

g) 9 \frac{1}{3} - 7 \frac{8}{9} =_____

h) 9 \frac{1}{2} - 8 \frac{3}{4} =_____

g) 3 \frac{3}{8} - 2 \frac{3}{4} =_____

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83 > 94

The correct option is A a2 + b2 – 2ab To compare the given numbers, we will make the denominator same. So, common denominator will be L.C.M of 4 and 3, which is 12. ⇒83=3212 And 94=2712 Clearly, 3212>2712 Hence, 83>94

$\frac{8}{3}$ $>$ $\frac{9}{4}$