The correct option is D 1 5/63 8/9+13/7 5/3 First we need to find the LCM of 9, 7 and 3, [ 3 amp;9,7,3; 3 amp;3,7,1; 7 amp;1,7,1; ...

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Standard V

Mathematics

Addition of Unlike Fractions

8/9+13/7-5/3=...

Question

$\frac{8}{9} + \frac{13}{7} - \frac{5}{3} = ?$

$\frac{61}{63}$

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$\frac{70}{63}$

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$1 \frac{2}{63}$

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$1 \frac{5}{63}$

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Solution

The correct option is D
$1 \frac{5}{63}$

$\frac{8}{9} + \frac{13}{7} - \frac{5}{3}$
First we need to find the LCM of 9, 7 and 3,
$\begin{matrix} 3 & 9, 7, 3 3 & 3, 7, 1 7 & 1, 7, 1 1, 1, 1 \end{matrix}$
LCM $= 3 \times 3 \times 7 = 63$

$\frac{8}{9} + \frac{13}{7} - \frac{5}{3}$ $= \frac{8 \times 7}{9 \times 7} + \frac{13 \times 9}{7 \times 9} - \frac{5 \times 21}{3 \times 21} = \frac{56 + 117 - 105}{63} = \frac{68}{63} = 1 \frac{5}{63}$

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Similar questions

Verify each of the following :

(i) $\frac{3}{7} \times \frac{- 5}{9} = \frac{- 5}{9} \times \frac{3}{7}$

(ii) $\frac{- 8}{7} \times \frac{13}{9} = \frac{13}{9} \times \frac{- 8}{7}$

(iii) $\frac{- 12}{5} \times \frac{7}{- 36} = \frac{7}{- 36} \times \frac{- 12}{5}$

(iv) $- 8 \times \frac{- 13}{12} = \frac{- 13}{12} \times (- 8)$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Evaluate:

(i) \frac{3}{7} + \frac{- 4}{9} - \frac{- 11}{7} - \frac{7}{9}

(i i) \frac{2}{3} + \frac{- 4}{5} - \frac{1}{3} - \frac{2}{5}

(i i i) \frac{4}{7} - \frac{- 8}{9} - \frac{- 13}{7} + \frac{17}{9}

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

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89+137−53=?

The correct option is D 1563 89+137−53 First we need to find the LCM of 9, 7 and 3, 39,7,333,7,171,7,11,1,1 LCM =3×3×7=63 89+137−53 =8×79×7+13×97×9−5×213×21=56 + 117 − 10563=6863=1563

$\frac{8}{9} + \frac{13}{7} - \frac{5}{3} = ?$