wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

a2 sin (BC)sin A+b2 sin (CA)sin B+c2 sin (AB)sin C=0

Open in App
Solution

a2 sin (BC)sin A+b2 sin (CA)sin B+c2 sin (AB)sin C=0asin A=bsin B=csin C=kLHSa2 sin (BC)sin A+b2 sin (CA)sin B+c2 sin (AB)sin C=ak sin (BC)+bk sin (CA)+ck sin (AB)=sin A sin (BC)+sin B sin (CA)+sin C sin (AB)=sin (π(B+C))sin (BC)+sin (π(C+A)) sin (CA)+sin (π(A+B))sin (AB)=sin (B+C) sin (BC)+sin (C+A) sin (CA)+sin (A+B)sin (AB)=sin2 Bsin2 C+sin2 Csin2 A+sin2 Asin2 B=0=RHS


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sine Rule
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon