Given (a^5a^3)× (a)^8 We know that [a^xa^y=a^x y and a^x· a^y=a^x+y] then =a^5 3+8=a^10 . ...

You visited us 7 times! Enjoying our articles? Unlock Full Access!

Sum of Infinite Terms of a GP

a5/a3× a8

Question

$(\frac{a^{5}}{a^{3}}) \times a^{8}$

Open in App

Solution

Given $(\frac{a^{5}}{a^{3}}) \times (a)^{8}$
We know that $[\frac{a^{x}}{a^{y}} = a^{x - y} a n d a^{x} \cdot a^{y} = a^{x + y}]$ then $= a^{5 - 3 + 8} = a^{10}$ .

Suggest Corrections

Similar questions

(\frac{a^{5}}{a^{3}}) \times a^{8}

(a^{8} + a^{5}) \div a^{3}

(\frac{a^{5}}{a^{3}}) \times a^{8}

a_{1}, a_{2}, a_{3}, a_{4}, \dots

a_{1} + a_{5} + a_{9} + . . . + a_{29} = 64

a_{3} + a_{8} + a_{22} + a_{27}

n

a_{n} = {(- 1)}^{n} n; a_{3}, a_{5}, a_{8}

Join BYJU'S Learning Program