$\frac{a^{m}}{a^{n}}$ = $a^{m - n}$ , m>n

True

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False

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Solution

The correct option is
A

True
As we have a standard result: $\frac{a^{m}}{a^{n}}$ = $a^{m - n}$ , $m > n$

Suggest Corrections

Similar questions

$\frac{(a^{m}) \times (a^{n})}{(a^{p})}$ can be rewritten as:

\frac{{(a^{m} \times a^{n} \times a^{l})}^{2}}{a^{m + n} \times a^{n + l} \times a^{l + m}}

Is $a^{m} \times a^{n} = a^{m + n}$

\frac{a^{m} \times a^{n}}{a^{m - n}}

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