wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

C01.2+C12.3+C23.4+...........+Cn(n+1)(n+2)=

Open in App
Solution

(1+x)n=nC0x0+nC1x1+nC2x2+........nCnxn
(1+x)n(n+1)=C0x1+C1x22+C2x33+........Cnxn+1n+1
(1+x)n=nC0x0+nC1x1+nC2x2+........nCnxn
(1+x)n+1(n+1)(n+2)=C0x1.2+C1x22.3+C2x33.4+........Cnxn+2(n+1)(n+2)
Put x=1
2n+1(n+1)(n+2)=C0x1.2+C1x22.3+C2x33.4+........Cnxn+2(n+1)(n+2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon