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Question

c1c0+2c2c1+3c3c2+.........+ncncn1=n(n+1)2

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Solution

Consider the given function:

c1c0+2c2c1+3c3c2+4c4c3+......+ncncn1

=n1+2n(n1)2!.1n+3n(n1)(n2)3!.1n(n1)2!+......+n.1n

=n+(n1)+(n2)+......1

=1+2+3+......+n

=n(n+1)2

Hence this is the answer.


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