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Question

C1C0+2C2C1++15C15C14=

A
100
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B
120
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C
-120
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D
None of these
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Solution

The correct option is B 120
C1C0+2C2C1+3C3C2++n.CnCn1=n(n+1)2
Putting n = 15, then 15×(15+1)2=120

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