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Question

cos2Θ3cosΘ+2sin2Θ

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Solution

We have,

cos2θ3cosθ+2sin2θ

cos2θ2cosθcosθ+2sin2θ

cosθ(cosθ2)1(cosθ2)sin2θ

(cosθ2)(cosθ1)sin2θ

(cosθ2)(cosθ1)(1cos2θ)

(cosθ2)(cosθ1)(1cosθ)(1+cosθ)

(cosθ2)(1+cosθ)

(2cosθ)(1+cosθ)

Hence this is the answer.

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