$\frac{c o s^{2} 56^{\circ} + c o s^{2} 34^{\circ}}{s i n^{2} 56^{\circ} + s i n^{2} 34^{\circ}} + 3 t a n^{2} 56^{\circ} \times t a n^{2} 34^{\circ} =$

0.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 4
$\frac{c o s^{2} 56^{\circ} + c o s^{2} 34^{\circ}}{s i n^{2} 56^{\circ} + s i n^{2} 34^{\circ}} + 3 t a n^{2} 56^{\circ} \times t a n^{2} 34^{\circ} = \frac{s i n^{2} (90^{\circ} - 56^{\circ}) + c o s^{2} 34^{\circ}}{c o s^{2} (90^{\circ} - 56^{\circ}) + s i n^{2} 34^{\circ}} + 3 c o t^{2} (90^{\circ} - 56^{\circ}) \times t a n^{2} 34^{\circ} = \frac{s i n^{2} 34^{\circ} + c o s^{2} 34^{\circ}}{c o s^{2} 34^{\circ} + s i n^{2} 34^{\circ}} + 3 c o t^{2} 34^{\circ} \times t a n^{2} 34^{\circ} = 1 + 3 = 4$

Suggest Corrections

Similar questions

\frac{{cos}^{2} 56^{\circ} + {cos}^{2} 34^{\circ}}{{sin}^{2} 56^{\circ} + {sin}^{2} 34^{\circ}} + 3 {tan}^{2} 56^{\circ} \times {tan}^{2} 34^{\circ}

\frac{\cos^{2} 56 ° + \cos^{2} 34 °}{\sin^{2} 56 ° + \sin^{2} 34 °} + 3 \tan^{2} 56 ° \tan^{2} 34 ° = ?

3 \frac{1}{2}

{sin}^{2} 34^{\circ} + {sin}^{2} 56^{\circ} + 2 tan 18^{\circ} tan 72^{\circ} - {cot}^{2} 30^{\circ}

Evaluate :

$s i n^{2} 34^{\circ} + s i n^{2} 56^{\circ} + 2 t a n 18^{\circ} t a n 72^{\circ} - c o t^{2} 30 \circ$

Join BYJU'S Learning Program