2 15-1- 2 15-1-MP PET 1998-

The correct option is B cot^2 15^∘ 1/cot^2 15^∘ + 1 = nbsp; cos^2 15^∘/sin^2 15^∘ nbsp; 1/cos^2 15^∘/sin^2 15^∘ + 1 = cos^2 15^∘ sin^2 15^∘/cos^2 15^ ...

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Byju's Answer

Standard XII

Mathematics

Cos(A+B)Cos(A-B)

2 15∘-1/ 2 15...

Question

$\frac{c o t^{2} 15^{\circ} - 1}{c o t^{2} 15^{\circ} + 1}$ =

[MP PET 1998]

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Solution

The correct option is B

$\frac{c o t^{2} 15^{\circ} - 1}{c o t^{2} 15^{\circ} + 1}$ = $\frac{\frac{c o s^{2} 15^{\circ}}{s i n^{2} 15^{\circ}} - 1}{\frac{c o s^{2} 15^{\circ}}{s i n^{2} 15^{\circ}} + 1}$

= $\frac{c o s^{2} 15^{\circ} - s i n^{2} 15^{\circ}}{c o s^{2} 15^{\circ} + s i n^{2} 15^{\circ}}$ = $c o s (30^{\circ})$ = $\frac{\sqrt{3}}{2}$

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cot215∘−1cot215∘+1 = [MP PET 1998]

The correct option is B cot215∘−1cot215∘+1 = cos215∘sin215∘−1cos215∘sin215∘+1 = cos215∘−sin215∘cos215∘+sin215∘ = cos(30∘) = √32

$\frac{c o t^{2} 15^{\circ} - 1}{c o t^{2} 15^{\circ} + 1}$ =

[MP PET 1998]