ddx{(1+x)12−(1−x)12}
None of these
ddx{(1+x)12−ddx(1−x)12}
We know, {ddxxn=nxn−1}
12(1+x)(12−1)×ddx(1+x)12(1−x)(12−1)×ddx(1−x)
(1+x)−12∗1−12(1−x)−12∗(−1)
(12√1+x+12√1−x)
option A is correct.