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Question

ddx[eaxsin(bx+c)]=

A
=eax[a sin(bx+c)+b cos(bx+c)]sin2(bx+c)
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B
=eax[a sin(bx+c)b cos(bx+c)]sin(bx+c)
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C
=eax[a sin(bx+c)b cos(bx+c)]sin2(bx+c)
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D
None of these
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Solution

The correct option is C =eax[a sin(bx+c)b cos(bx+c)]sin2(bx+c)
ddx(eaxsin(bx+c))=aeaxsin(bx+c)beaxcos(bx+c){sin(bx+c)}2=eax[a sin(bx+c)b cos(bx+c)]sin2(bx+c)

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