Question

$\frac{d}{dx}\left[log\left(\sqrt{\frac{1-cosx}{1+cosx}}\right)\right]=$

• A. cosx
• B. sinx
• C. cosecx
• D. secx

Answer 1

The correct option is C

cosecx

$\frac{1-cosx}{1+cosx}=ta{n}^2\frac{x}{2}\Rightarrow log\sqrt{\frac{1-cosx}{1+cosx}}=logtan\frac{x}{2}$

use chain rule, get the answer