D-d x-tan -15 x-1-6 x2-

The correct option is D 3/1+9x^2+2/1+4x^2 5x=2x+3x.take 2x=tanA and 3x=tanB then y=tan^ 12x+tan^ 13x ...

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Special Integrals - 1

d/d x[tan -15...

Question

$\frac{d}{d x} [t a n^{- 1} (\frac{5 x}{1 - 6 x^{2}})] =$

$\frac{1}{1 + 4 x^{2}}$

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$\frac{1}{1 + 4 x^{2}}$

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$\frac{2}{1 + x^{2}} + \frac{3}{1 + 9 x^{2}}$

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$\frac{3}{1 + 9 x^{2}} + \frac{2}{1 + 4 x^{2}}$

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Similar questions

\frac{d y}{d x}

y = {tan}^{- 1} (\frac{5 x + 1}{3 - x - 6 x^{2}})

y = {tan}^{- 1} \frac{5 x}{1 - 6 x^{2}}, - \frac{1}{\sqrt{6}} < x < \frac{1}{\sqrt{6}}

\frac{d y}{d x}

x

{tan}^{- 1} (\frac{5 x}{1 - 6 x^{2}})

\frac{d y}{d x} if y = t a n^{- 1} (\frac{5 x + 1}{3 - x - 6 x^{2}})

y = {tan}^{- 1} \frac{5 a x}{a^{2} - 6 x^{2}}

\frac{d y}{d x}

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