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Question

dydx+x sin y=logxe is a linear differential equation of first order.

A
True
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B
False
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Solution

The correct option is B False
So it looks like a linear differential equation Right? But it is not. You are missing something. Here if you compare it to basic form of linear differential equation dydx+P(x)y=Q(x) the second term x sin y is a misfit for L.D.E because we cannot have any transcendental functions of y (dependent variable) in the equation. Nor we can have transcendental functions of dydx. So had it been sin(dydx)+xy=log x still it would not have been a linear differential equation.

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