-129 - 129 - 387-187 - 187 - 561 -1129 - 129-129 - 187-187 - 187-

The correct option is C 948 ( a^3+b^3 )= ( a+b ) ( a^2 ab+b^2 ) [3 ( 129^3+187^3 ) ]/ (129^2+187^2 129*187) [3 ( a^3+b^3 ) ]/ ( a^2 ab+b^2 )=3 ( a+b ) ...

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Byju's Answer

Standard VIII

Mathematics

Expansion of (x+y)^2

[129 × 129 × ...

Question

$\frac{[(129 \times 129 \times 387) + (187 \times 187 \times 561)]}{[129 \times 129 - 129 \times 187 + 187 \times 187]} =$

316

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748

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948

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Solution

The correct option is C
948

$(a^{3} + b^{3}) =$ $(a + b) (a^{2} - a b + b^{2})$ $\frac{[3 (129^{3} + 187^{3})]}{(129^{2} + 187^{2} - 129 * 187)}$ $\frac{[3 (a^{3} + b^{3})]}{(a^{2} - a b + b^{2})} = 3 (a + b)$

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[(129×129×387)+(187×187×561)][129×129−129×187+187×187]=

The correct option is C 948 (a3+b3)= (a+b)(a2−ab+b2) [3(1293+1873)](1292+1872−129∗187) [3(a3+b3)](a2−ab+b2)=3(a+b)

$\frac{[(129 \times 129 \times 387) + (187 \times 187 \times 561)]}{[129 \times 129 - 129 \times 187 + 187 \times 187]} =$

The correct option is C
948

$(a^{3} + b^{3}) =$ $(a + b) (a^{2} - a b + b^{2})$ $\frac{[3 (129^{3} + 187^{3})]}{(129^{2} + 187^{2} - 129 * 187)}$ $\frac{[3 (a^{3} + b^{3})]}{(a^{2} - a b + b^{2})} = 3 (a + b)$