Byju's Answer
Standard XII
Mathematics
Standard Formulae - 2
sin 3 x/cos 4...
Question
s
i
n
3
x
(
c
o
s
4
x
+
3
c
o
s
2
x
+
1
)
t
a
n
−
1
(
s
e
c
x
+
c
o
s
x
)
d
x
=
A
t
a
n
−
1
(
s
e
c
x
+
c
o
s
x
)
+
c
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B
l
o
g
|
t
a
n
−
1
(
s
e
c
x
+
c
o
s
x
)
|
+
c
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C
1
(
s
e
c
x
+
c
o
s
2
x
)
2
+
c
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D
l
o
g
|
s
e
c
x
+
c
o
s
x
|
+
c
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Solution
The correct option is
A
l
o
g
|
t
a
n
−
1
(
s
e
c
x
+
c
o
s
x
)
|
+
c
Put
t
a
n
−
1
(
s
e
c
x
+
c
o
s
x
)
=
f
(
x
)
f
1
(
x
)
=
s
i
n
3
x
c
o
s
4
x
+
3
c
o
s
2
x
+
1
∴
∫
f
1
(
x
)
f
(
x
)
=
l
o
g
|
f
(
x
)
|
+
c
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