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Question

sin3x(cos4x+3cos2x+1)tan1(secx+cosx)dx=
  1. log|tan1(secx+cosx)|+c
  2. 1(secx+cos2x)2+c
  3. tan1(secx+cosx)+c
  4. log|secx+cosx|+c


Solution

The correct option is A log|tan1(secx+cosx)|+c
Put tan1(secx+cosx)=f(x)f1(x)=sin3xcos4x+3cos2x+1f1(x)f(x)=log|f(x)|+c

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